python天生4人扑克牌手牌

python天生4人扑克牌手牌

连载一段网友用python写的扑克牌发放营业牌照代码 两个本领天生,解释掉的实质为一次发够13张 '''2 随机天生扑克牌牌的4手牌(4部分的牌局,没手13张,没有巨细王)''' import random num = [] #代办红桃,方块,黑桃,梅花 for i in ['Hearts','Cube','Spades','plum']: for j in ['2','3','4','5','6','7','8','9','10','J','Q','K','A']: num.append(i+j) #random.shuffle() 讲序列中的实质随机打乱 random.shuffle(num) #天生二维game game = [[] for i in range(4)] #一次性发13张 ''' for i in range(4): while len(num) > 0: game[i].append(num[0]) num.pop(0) if len(game[i])==13 : break...